Question

transforme as unidades de temperaturas nos itens abaixo

52°C=_____°F
780k=_____°C
82°F=_____°C
150K=_____°F​

Answer 1

$\frac{52}{5} = \frac{tf - 32}{9}$

Multiplica cruzado:

$5tf - 160 = 468$

$5tf = 468 + 160$

$tf = 628 \div 5$

$tf = 125.6$

125,6°F

$\frac{780 - 273}{5} = \frac{tc}{5}$

$5tc = 507.5$

$tc = 2535 \div 5$

$tc = 507$

507°C

$\frac{82 - 32}{9} = \frac{tc}{5}$

$9tc = 50.5$

$tc = 250 \div 9$

$tc = 27.77$

27,78°C

$\frac{150 - 273}{5} = \frac{tf - 32}{9}$

$5tf - 160 = - 123.9$

$5tf = - 1.107 + 160$

$tf = -947\div 5$

$tf = - 189.4$

-189°F

Espero ter ajudado!