Question

Transforme as seguintes temperatura para a escala Kelvin e para a escola Fahrenheit
A)T = 0°C
B) T = 27°C
C) T= -30°C

Answer 1

Em fahrenheit:

Letra a)

$\frac{Tc}{5} \ = \ \frac{Tf \ - \ 32}{9}$

$\frac{0}{5} \ = \ \frac{Tf \ - \ 32}{9}$

$0 \ = \ \frac{Tf \ - \ 32}{9}$

$0 \ * \ 9 \ = \ Tf \ - \ 32$

$0 \ = \ Tf \ - \ 32$

$0 \ + \ 32 \ = \ Tf$

$\boxed{32 \ \ºF \ = \ Tf}$

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Letra b)

$\frac{Tc}{5} \ = \ \frac{Tf \ - \ 32}{9}$

$\frac{27}{5} \ = \ \frac{Tf \ - \ 32}{9}$

$5,4 \ = \ \frac{Tf \ - \ 32}{9}$

$5,4 \ * \ 9 \ = \ Tf \ - \ 32$

$48,6 \ = \ Tf \ - \ 32$

$48,6 \ + \ 32 \ = \ Tf$

$\boxed{80,6 \ \ºF \ = \ Tf}$

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Letra c)

$\frac{Tc}{5} \ = \ \frac{Tf \ - \ 32}{9}$

$\frac{-\ 30}{\ \ \ 5} \ = \ \frac{Tf \ - \ 32}{9}$

$-\ 6 \ = \ \frac{Tf \ - \ 32}{9}$

$- \ 6 \ * \ 9 \ = \ Tf \ - \ 32$

$- \ 54 \ = \ Tf \ - \ 32$

$- \ 54 \ + \ 32 \ = \ Tf$

$\boxed{- \ 22 \ \ºF \ = \ Tf}$

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Em kelvin:

Letra a)

Tk = Tc + 273

Tk = 0 + 273

Tk = 273 K

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Letra b)

Tk = Tc + 273

Tk = 27 + 273

Tk = 300 K

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Letra c)

Tk = Tc + 273

Tk = (-30) + 273

Tk = 243 K