Question

Transforme 40̊° Celsius em fahrenheit




Transforme 100° F em Celsius




Transforme 25° C em Fahrenheit





Transforme 125° F em Celsius

Answer 1

Resposta:

40 °C em fahrenheit

$\frac{TC}{5} =\frac{TF-32}{9} \\\frac{40}{5} =\frac{TF-32}{9}\\9 . 40= 5(TF-32)\\360=5TF -160\\360+160=5TF\\TF=\frac{520}{5}\\TF= 104^0F$

100°F em Celsius

$\frac{TF-32}{9} =\frac{Tc}{5}\\\frac{100-32}{9}=\frac{TC}{5} \\5(100-32)=9Tc\\5 . 68=9TF\\340= 9TF\\TF=\frac{340}{9} \\TF=37,7^0F$

25° C em Fahrenheit

$\frac{Tc}{5}=\frac{Tf-32}{9}\\\frac{25}{5} =\frac{TF-32}{9} \\9.(25)=5(TF-32)\\225=5TF-160\\225+160=5TF\\385=5TF\\TF=\frac{385}{5}\\TF=77^0F$

125° F em Celsius

$\frac{TF-32}{9}=\frac{TC}{5}\\\frac{125-32}{9}=\frac{TC}{5}\\5(125-32)=9TC\\5 . 93 = 9TC\\465=9Tc\\TC=\frac{465}{9}\\Tc= 51,6^0 C$