Question

Transformar 122° F nas escalas Celsius e Kelvin.

Answer 1

θc/5 = θf - 32/9 = θk - 273/5

θc/5 = 122 - 32/ 9
θc/5 = 90/9
9θc = 450
θc = 450/9
θc= 50 °C

θc/5 = θk - 273/5
50/5 = θk - 273/5
Corta o denominador
50 = θk - 273
- θk = -273 -50
- θk = - 223 (-1)
θk = 223