Question

transformando os números mistos, 3 2/5, 2 1/7 e 2 5/6 em frações impróprias, podemos afirmar que:

a: 3 2/5 > 18/5
b: 2 1/7 < 15/7
c: 2 5/6 = 13/6
d: 3 2/5 < 11/5
e: 2 5/6 < 19/6​

Answer 1

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$\sf{3~\dfrac{2}{5}=\dfrac{3\cdot5+2}{5}=\dfrac{17}{5}}\\\sf{2~\dfrac{1}{7}=\dfrac{2\cdot7+1}{7}=\dfrac{15}{7}}\\\sf{2~\dfrac{5}{6}=\dfrac{2\cdot6+5}{6}=\dfrac{17}{6}}$

$\tt a)~\sf{3~\dfrac{2}{5}>\dfrac{18}{5}~Falso~pois}\\\sf{\dfrac{17}{5}<\dfrac{18}{5}}$

$\tt a)~\sf2~\dfrac{1}{7}<\dfrac{15}{7}~falso~pois\\\sf 2~\dfrac{1}{7}=\dfrac{15}{7}$

$\tt c)~\sf{2~\dfrac{5}{6}=\dfrac{13}{6}~falso~pois}\\\sf 2~\dfrac{5}{6}=\dfrac{17}{6}$

$\tt d)~\sf{3~\dfrac{2}{5}<\dfrac{11}{5}~falso~pois}\\\sf \dfrac{17}{5}>\dfrac{11}{5}$

$\tt e)~\sf{2~\dfrac{5}{6}<\dfrac{19}{6}~verdadeiro~pois}\\\sf \dfrac{17}{6}<\dfrac{19}{6}$