Question

Trabalho Resolva as seguintes equações 1) 4x-1=3(X-1)
2) 3(X-2)=2X-4
3) 2(X-1)=3x+4
4) 2X+3x+9=8(6-X)
5) 4(X+10)-2(X-5)=0
6) 7(X-1)-2(X-5)=X-5
7) (4X+6)-2x=(X-6)+10+14
8) (X-3)-(X+2)+2(X-1)-5=0
9) 3(5-X)-3(1-2X)=42
10)5(X-3)-4(X+2)=2+3(1-2X)​

Answer 1

Resposta:

1) 4x-1=3(X-1)

$4x - 1 = 3x - 3 \\ 4x - 1 - 3x + 3 = 0 \\ x + 2 = 0 \\ x = - 2$

2) 3(X-2)=2X-4

$3x - 6 = 2x - 4 \\ 3x - 6 - 2x + 4 = 0 \\ x - 2 = 0 \\ x = 2$

3) 2(X-1)=3x+4

$2x - 2 - 3x - 4 = 0 \\ - x - 6 = 0 \\ - x = 6 \times ( - 1) \\ x = - 6$

4) 2X+3x+9=8(6-X)

$5x + 9 = 48 - 8x \\ 5x + 9 - 48 + 8x = 0 \\ 13x - 39 = 0 \\ 13x = 39 \div (13) \\ x = 3$

5) 4(X+10)-2(X-5)=0

$4x + 40 - 2x + 10 = 0 \\ 2x + 50 = 0 \\ 2x = - 50 \div (2) \\ x = - 25$

6) 7(X-1)-2(X-5)=X-5

$7x - 7 - 2x + 10 = x - 5 \\ 5x + 3 - x + 5 = 0 \\ 4x + 8 = 0 \\ 4x = - 8 \div (4) \\ x = - 2$

7) (4X+6)-2x=(X-6)+10+14

$4x + 6 - 2x = x - 6 + 24 \\ 2x + 6 = x + 18 \\ 2x + 6 - x - 18 = 0 \\ x - 12 = 0 \\ x = 12$

8) (X-3)-(X+2)+2(X-1)-5=0

$x - 3 - x - 2 + 2x - 2 - 5 = 0 \\ 2x - 12 = 0 \\ 2x = 12 \div (2) \\ x = 6$

9) 3(5-X)-3(1-2X)=42

$15 - 3x - 3 + 6x = 42 \\ 3x + 12 = 42 \\ 3x + 12 - 42 = 0 \\ 3x - 30 = 0 \\ 3x = 30 \div (3) \\ x = 10$

10)5(X-3)-4(X+2)=2+3(1-2X)

$5x - 15 - 4x - 8 = 2 + 3 - 6x \\ x - 23 = 5 - 6x \\ x - 23 - 5 + 6x = 0 \\ 7x - 28 = 0 \\ 7x = 28 \div (7) \\ x = 4$