Question

The sum of four consecutive positive integer is x .in term of x what is the sum of 2 nd and 3 rd integer​

Answer 1

Being a the smallest integer in the sequence:

$a + (a+1) +(a+2)+(a+3) = x$

$4 \cdot a + 6 = x$

The second and third integer, are: $a+1$ and $a+2$, respectively.

Its sum:

$a+1+a+2 = 2 \cdot a + 3 = \boxed{\dfrac{x}{2}}$

Answer 2

Resposta:

Explicação passo-a-passo:

First number = k

Second number = k+1

Third number = k+2

Fourth number = k+3

x = First+Second + Third+Fourth

x=k+k+1+k+2+k+3

x=4k+6

4k=x-6

k=(x-6)/4

Second + Third = k+1+k+2=2k+3

Second + Third = 2k+3

Second + Third = $2.\dfrac{(x-6)}{4}+3=\dfrac{x-6}{2}+3=\dfrac{x-6}{2}+\dfrac{6}{2}=\dfrac{x}{2}$