Question

tg x= -√3/3 para 0 ≤x ≤2π ?
S = {π/3 ,2π/3}
S = {π/6 ,2π/3}
S = {5π/6 ,11π/6}
S = {π/2 ,π/3}
S = {π/2 ,π/6}

Answer 1

tgx = -√3/3 ====> tg π/6=√3/3
a tg é (-) no 2° e 4° Quad.
2° Q => x' = π -π/6= 5π/6 ✓
4° Q => x"=2π -π/6= 11π/6✓
===> S = {5π/6 ,11π/6}