Question

$x4-10x2+24=0$

Answer 1

fazendo :

$\boxed{ \left \{ {{x^4=y^2} \atop {x^2=y}} \right. }$

Aplicando ;

$y^2-10y+24=0\\ \\\Delta=(-10)^2-4*1*24\\\Delta=100-96 \\\Delta=4$

$y= \frac{10\pm2}{2} \\ \\y'=6\\ \\y''=4$

determinar as raízes

$x= \sqrt{y'}\\ \\x= \sqrt{y''}$

$x= \pm\sqrt{6} \\ \\x=\pm2$

$S=\{2,+2,- \sqrt{6},+ \sqrt{6} }}$