Question

$x=(- \frac{1}{3} ) ^{3} + \left[3 ^{1-(-3) ^{-1} } ] ^{-2}$

Answer 1

$x=(-\frac{1}{3})^3+[3^1-(-3)^{-1}]^{-2} \\ \\ x=-\frac{1}{27}+[3-\frac{1}{-3}]^{-2} \\ \\ x=-\frac{1}{27}+[3+\frac{1}{3}]^{-2} \\ \\ x=-\frac{1}{27}+[\frac{10}{3}]^{-2} \\ \\ x=-\frac{1}{27}+(\frac{3}{10})^2 \\ \\ \boxed{x=-\frac{1}{27}+\frac{9}{100 }=\frac{143}{2700}}$