Question

$x { }^{2} - 8x + 12 = 0$
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Answer 1

Resposta:

S={ 2 ,6}

Explicação passo-a-passo:

x² -8x +12=0

a=1

b=-8

c=12

Δ=b²-4ac

Δ=(-8)²-4(1)(12)

Δ=64=48

Δ=16

$x={-b\pm\sqrt{\Delta} \over2a}={-(-8)\pm\sqrt{16} \over2(1)}={8\pm4\over2}\\ \\ x'={8+4\over2}={12\over2}=6\\ \\ x"={8-4\over2}={4\over2}=2$