Question

$x^{2}-7 x^{2}+10=0$ qual é ore sultadp

Answer 1

$x^{2} -7x+10=0 \Delta= b^{2} -4.a.c= \Delta= -7^{2} -4.1.10= \Delta=49-40=9 x1=-+(-7) \sqrt{9} /2=7-3/2=4/2=2  x2=-+(-7) \sqrt{9} /2=7+3/2=10/2=5$


S{2,5}

Answer 2

$x^2-7x+10=0$
$a= 1 b= -7 c= 10$

$x= -b\pm\frac{\sqrt{b^2-4.a.c}}{2.a}$

$x=- (-7)\pm\frac{\sqrt{(-7)^2-4.1.10}}{2.1}$
 
$x= 7\pm\frac{\sqrt{49-40}}{2}$

$x= 7\pm\frac{\sqrt{9}}{2}$

$x= 7\pm\frac{{3}}{2}$
 
$x'= 5$
$x''= 2$

$S:[2,5]$