Question

$x^{2}+6x-7=0$

Answer 1

Δ= b²-4ac
Δ= 6²- 4.1.(-7)
Δ= 36+28
Δ= 64

$X= \frac{-6+- \sqrt{64} }{2} \\ X'= \frac{6+8}{2} \\ X'= \frac{14}{2} \\ X"= 7 \\ \\ x"= \frac{6-8}{2} \\ x"= -1$