Question

$x {}^{2} + 3x - 6 = - 8$
ajuda pleacee​

Answer 1

${x}^{2} + 3x - 6 = - 8$

${x}^{2} + 3x - 6 + 8$

${x}^{2} + 3x + 2 = 0$

∆ = 3² - 4.1.3

∆ = 9 - 8

∆ = 1

$x = \frac{ - 3 + - \sqrt{1} }{2 \times 1}$

$x = \frac{ - 3 + - 1}{2}$

$x = \frac{ - 3 + 1}{2} = - 1 \\ x = \frac{ - 3 - 1}{2} = - 2$

Answer 2

Resposta:

S={-1, -2}

Explicação passo-a-passo:

x² +3x -6 =-8

x² +3x -6 +8=0

x²+3x +2=0

a=1

b=3

c=2

∆=b² -4.a.c

∆= 3²-4.1.2

∆= 9 - 8

∆= 1

x= - b ±√∆/2.a

x= - 3 ±√1/2.1

x= -3 ±1/2

x1= -3+1/2= -2/2=-1

x2= -3-1/2= -4/2=-2