Question

${x}^{2} - 3 \times + 4x - 12 - 14 = x - 2 - { \times }^{2} + 2x$ aplicando a formula de Bhaskara

Answer 1

$x^{2} -3x+4x-12-14=x-2- x^{2} +2x \\ x^{2} +x-26-3x-2- x^{2} \\ x^{2} +x-26-3x+2+ x^{2} =0 \\ 2 x^{2} -2x-24=0 \\ x^{2} -x-12=0 \\ x^{2} +3x-4x-12=0 \\ x*(x+3)-4(x+3)=0 \\ (x+3)*(x-4)=0 \\ x+3=0 \\ x-4=0 \\ x=-3 \\ x=4 \\ \\ As-solucoes-finais-sao \\ \\ x_{1} =-3 \\ x_{2} =4$