Question

${x}^{2} - 3 = \frac{x - 3}{6}$

Answer 1

$\frac{x^{2}-3}{1}=\frac{x-3}{6}$

$6(x^{2}-3) =x-3$

$6x^{2}-18=x-3$

$6x^{2}-x-18+3=0$

$6x^{2} -x-15=0$

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$a=6$

$b=-1$

$c=-15$

Δ=$(-1)^{2}-(4).(6).(-15)$

Δ=$1+360$

Δ=$361$

$x1=\frac{-b+\sqrt{361}}{2.a}=\frac{1+19}{2.6}=\frac{20}{12}=\frac{5}{3}$

$x1=\frac{-b-\sqrt{361}}{2.a}=\frac{1-19}{2.6}=-\frac{18}{12}=-\frac{3}{2}$