Question

${x}^{2} + 2x - 8 = 0$
​

Answer 1

Explicação passo-a-passo:

x²+2x-8=0

a=1

b=2

c=-8

∆=b²-4ac

∆=2²-4×1×-8

∆=4+32

∆=36

-b±√∆/2a

-2±√36/2×1

-2±6/2

x¹=-2+6/2=4/2=2

x²=-2-6/2=-8/2=-4

Answer 2

Equação do 2° Grau

$\boxed{\begin{array}{lr} x^2+2x-8=0 \end{array}}$

vou resolver utilizando a

fórmula de bhaskara

$\boxed{\begin{array}{lr} ax^2+bx+c=0 \end{array}}$

$\boxed{\begin{array}{lr} x^2+2x-8=0 \rightarrow\begin{cases} a=1\\b=2\\c=-8 \end{cases} \end{array}}$

Agora precisamos achar  o valor do discriminante

mais conhecido como Delta ($\Delta$)

$\boxed{\begin{array}{lr} \Delta=b^2-4ac\\\Delta=2^2-4.1.-8\\\Delta=4+32 \\\Delta=36 \end{array}}$

tendo o valor de delta

fica mais fácil para achar a raiz da equação.

$\boxed{\begin{array}{lr} x=\dfrac{-2\pm6}{2} \end{array}}\\\boxed{\begin{array}{lr} x'=\dfrac{-2+6}{2} \end{array}}\\\boxed{\begin{array}{lr} x'=\dfrac{4}{2} \end{array}}\\\boxed{\begin{array}{lr} x'=2 \end{array}}\\\boxed{\begin{array}{lr} x''=\dfrac{-2-6}{2} \end{array}}\\\boxed{\begin{array}{lr} x''=\dfrac{-8}{2} \end{array}}\\\boxed{\begin{array}{lr} x''=-4 \end{array}}\\\\S=\{2,-4\}\ \ \checkmark$

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