Question

$x {}^{2} + 2x - 8 = 0$
​

Answer 1

Resposta:

x² + 2x - 8 = 0

A = 1 / B = 2 / C = -8

Δ = b² - 4 . a . c

Δ = 2² - 4 . 1 . (-8)

Δ = 4 - (-32)

Δ = 36

x = - b ± √Δ  / 2 · a

x¹ = - 2 + √36 / 2 . 1

x¹ = -2 + 6 / 2

x¹ = 4 / 2 = 2

x² = - 2 - √36 / 2 . 1

x² = -2 - 6 / 2

x² = -8 / 2 = -4

S = {2, -4}

Answer 2

Explicação passo-a-passo:

$x^{2} + 2x - 8 \: = 0 \\ \\ d = 2 ^{2} - 4.1.( - 8) \\ \\ d = 4 + 32 \\ \\ d = 36 \\ \\ x = \frac{ - 2 + 6}{2} \\ \\ x = \frac{4}{2} \\ \\ x = 2\\ \\ \\ x = \frac{ - 2 - 6}{2} \\ \\ x = \frac{ - 8}{2} \\ \\ x = - 4 \\ \\ s \: ( - 4 \: e \: 2 \: )$