Question

$x ^{2} - 2 x + 1$
f)
$121x ^{2} + 22x + 1$
​

Answer 1

$\large\boxed{\boxed{\boxed{{Ol\'a}}}}}$

$A)\:x^2-2x+1=0$

$onde:$

a = 1 ; b = -2 e c = 1

lembrando que:

$\Delta=b^2-4×a×c$

$\Delta=(-2)^2-4×1×1$

$\Delta=4-4$

$\Delta=0$

$\LARGE{x_{1},_{2}=\frac{-b±\sqrt{\Delta}}{2.a}}$

$\LARGE{x_{1}=\frac{-b+\sqrt{\Delta}}{2.a}}$

$\LARGE{x_{1}=\frac{-(-2)+\sqrt{0}}{2.1}}$

$\LARGE{x_{1}=\frac{+2+0}{2}}$

$\LARGE{x_{1}=\frac{2}{2}}$

$\large\boxed{{x_{1}=1}}}}}$\:$\checkmark$

$\LARGE{x_{2}=\frac{-b-\sqrt{\Delta}}{2.a}}$

$\LARGE{x_{2}=\frac{-(-2)-\sqrt{0}}{2.1}}$

$\LARGE{x_{2}=\frac{+2-0}{2}}$

$\LARGE{x_{2}=\frac{2}{2}}$

$\large\boxed{{x_{2}=1}}}}}$\:$\checkmark$

$B)\:\LARGE{121x^2+22x+1}$

Neste exerçicio vamos fazer directo sem mais delongas.

$\LARGE{x_{1},_{2}=\frac{-b±\sqrt{b^2-4×a×c}}{2.a}}$

$\LARGE{x_{1},_{2}=\frac{-22±\sqrt{22^2-4×121×1}}{2.121}}$

$\LARGE{x_{1},_{2}=\frac{-22±0}{242}}$

$\LARGE{x_{1},_{2}=\frac{-22}{242}}$

$\LARGE{x_{1},_{2}=\frac{-1}{11}}$

:::::boa interpretação::::

07.04.2019