Question

$x^{2} +16x+64=0$

Answer 1

Olá, boa noite ☺

Resolução:

x² + 16x + 64 = 0

Coeficientes:

a= 1
b= 16
c= 64

$\\ \Delta=b^2-4.a.c \\ \Delta= 16^{2} -4.1.64 \\ \Delta=256-256 \\ \Delta= 0 \\ \\ \texttt{Valores\ de \ x:} \\ \\ x= \frac{-b \pm \sqrt{\Delta} }{2.a} \\ \\ x= \frac{-16 \pm \sqrt{0} }{2.1} \\ \\ x'= \frac{-16+0}{2} = \frac{-16}{2} =-8 \\ \\ x''= \frac{-16-0}{2} = \frac{-16}{2} =-8$

Bons estudos :)