Question

$x {}^{2} -13x + 22 = 0$
equação do 2 grau- Fórmula de bháskara​

Answer 1

x²-13x+22=0

vamos calcular o delta

∆=b²-4ac

∆=(-13)²-4×1×22

∆=169-88

∆=81

x1/2=-b±√∆/2×a

X1/2= -(-13)±√81/2×1

x1/2= 13±9/2

x1=13+9/2

x1= 22/2=11

x2=13-9/2

x2= 4/2

x2= 2