Question

${x}^{2} - 10x + 25 = 0$
utilizando o processo de Bháskara​

Answer 1

a= 1
b= -10
c= 25

delta:
x= b^2 - 4.a.c
x= -10^2 - 4.1.25
x= 100.100
x= 1000

bháskara: