Question

${ \times }^{2} - 3 \times + 2 = 0$
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Answer 1

x²-3x+2=0

a=1

b=-3

c=2

∆= b²-4.a.c

∆= (-3)²-4.1.2

∆=9-8

∆=1

x= -b±√∆/2.a

x= -(-3)±√1/2.1

x= 3±1/2

x1=3+1/2=4/2=2

x2= 3-1/2=2/2=1

S={ 2, 1 }