Question

$\sqrt{9 + \sqrt{6 = } }$
$\sqrt{25 + \sqrt{81} }$
$\sqrt{0 + \sqrt{1} }$

$\sqrt{64 + \sqrt{100} }$
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Answer 1

Resposta:

Explicação passo-a-passo:

$\sqrt{9 + \sqrt{6} } = \sqrt{(9 + \sqrt{6}) . ( (9 - \sqrt{6})} = \sqrt{81 - 6} = \sqrt{75} \\\\\sqrt{25 + \sqrt{81} } = \sqrt{25 + 9} = \sqrt{34} \\\\\sqrt{0 +\sqrt{1} } = \sqrt{0 + 1} = \sqrt{1} = 1\\\\\sqrt{64 +\sqrt{100} } = \sqrt{64 + 10} = \sqrt{74}$