Question

$\sqrt{64} + \sqrt[3]{64} + \sqrt[6]{64} =$
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Answer 1

$\sqrt{64} + \sqrt[3]{64} + \sqrt[6]{64} = \\ \\ \sqrt{ {8}^{2} } + \sqrt[3]{ {4}^{3} } + \sqrt[6]{ {2}^{6} } = \\ \\ 8 + 4 + 2 = 14$

Answer 2

Oie, Td Bom?!

$\sqrt{64} + \sqrt[3]{64} + \sqrt[6]{64}$

$8 + 4 + 2$

$10 + 4$

$14$

Att. Makaveli1996