Question

$\sqrt{64} + \sqrt[3]{ - 64} + \sqrt[6]{64}$

Answer 1

√64 + ³√-64 + ^6√64
$\sqrt{64} + \sqrt[3]{-64} + \sqrt[6]{64} = \sqrt{ 8^{2} } + \sqrt[3]{- 4^{3} } + \sqrt{ 2^{6} }$
=8-4+2
=4+2
=6