Question

$\sqrt[6]{5^{2}-2^{5} }$

Answer 1

$\sqrt[6]{{5}^{2} - {2}^{5}} = \sqrt[6]{25 - 32} = \sqrt[6]{ - 7} = \not \exists$

Answer 2

$\sqrt[6]{25 - 32} \\ \sqrt[6]{25} - \sqrt[6]{32} \\ {25}^{ \frac{1}{6} } - {32}^{ \frac{1}{6} } \\ 1.7099759467 - 1.7817974363 \\ - 0.0718214896$