Question

($(\sqrt{36})^{40} . ( \sqrt{6} ) : 6^{2} . 36^{0,5}$

COMO FAZ????????

Answer 1

$( \sqrt{36})^4^0 . ( \sqrt{6} )^4: 6^2 . 36^0^,^5$
$( \sqrt{6^2})^4^0 . ( \sqrt{6^4)} : 6^2 . 36^0^,^5$
$( 6)^4^0 . ( \sqrt{1296)} : 6^2 . 36^0^,^5$
$\frac{6^4^0. 36 }{6^2.36^0^,^5}$
$\frac{6^4^0. 6^2 }{6^2.(6^2)^0^,^5}$
$\frac{6^4^2}{6^3}$
$6^3^9$