Question

$\sqrt[3]{64x}$ + 6 = 10

Answer 1

$\sqrt[3]{64x}+6 =10$

$4 \sqrt[3]{x} + 6 =10$

$4 \sqrt[3]{x}=10 - 6$

$4 \sqrt[3]{x}=4--> \sqrt[3]{x}=1$

$( \sqrt[3]{x})^3= 1^3-->x = 1$