Question

$\sqrt[3]{4 ^{x} } = \frac{1}{8}$

Answer 1

$\sqrt[n]{4^x} = 2^{ \frac{2x}{3} } = \\\\ 2^{ \frac{2x}{3} } = 2^{-3} = \\\\ \frac{2x}{3} = -3 \\\\ x = - \frac{9}{2}$

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