Question

$\sqrt{2x - 1} + 6 = 9$
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Answer 1

$\sqrt{2 x - 1} + 6 = 9$

$\ \sqrt{2x - 1} = 9 - 6$

$\sqrt{2x - 1} = 3$

$2x - 1 = {3}^{2}$

$2x - 1 = 9$

$2x = 10$

$x = \frac{10}{2} = 5$

Então x=5

Answer 2

Resposta:

$\sqrt{2x-1} +6=9\\ \\ \sqrt{2x-1} =9-6\\ \\ \sqrt{2x-1}=3\\ \\ 2x-1=3^{2} \\ \\ 2x-1=9\\ \\ 2x=9+1\\ \\ 2x=10\\ \\ x=\frac{10}{2} \\ \\ x=5$