Question

$\sqrt{2 - x}$ = x

Ajude-me Pfvv

Answer 1

$x=\sqrt{2-x} \\ \\ x^{2} =2-x\\\\ x^{2} +x-2=0$

$x= \frac{-1+- \sqrt{9} }{2} \\ \\ x= \frac{-1+-3}{2} \\ \\ x'= \frac{-4}{2} =-2 \\ \\ x''= \frac{2}{2} =1 \\ \\ Solucao: S=(1;-2)$

Answer 2

Bom, vamos lá.

$2 - x = {x}^{2}$

x² + x -2 = 0

∆= b²-4ac
∆= 1 + 8
∆= 9

x' = -1 + √9/2
x' = -1+3/2
x' = 1


x" = -1-√9/2
x" = -1-3/2
x" = -2


Solução { -2, 1}