Question

$\sqrt{ 16} + \sqrt{ \frac{1}{9} } + \sqrt{ \frac{1}{4} } + {7}^{1} - {12}^{0}$
me ajudem a resolver essa expressão numérica com passo a passo pfvr?​

Answer 1

$\sqrt{16} + \sqrt{ \frac{1}{9} } + \sqrt{ \frac{1}{4} } + {7}^{1} - {12}^{0} = \\ \\ \sqrt{ {4}^{2} } + \sqrt{ \frac{1}{ {3}^{2} } } + \sqrt{ \frac{1}{ {2}^{2} } } + 7 - 1 = \\ \\ 4 + \frac{1}{3 } + \frac{1}{2} + 7 - 1 = \\ \\ \frac{4 \times 6}{6} + \frac{1 \times 2}{6} + \frac{1 \times 3}{6} + \frac{7 \times 6}{6} - \frac{1 \times 6}{6} = \\ \\ \frac{24}{6} + \frac{2}{6} + \frac{3}{6} + \frac{42}{6} - \frac{6}{6} = \\ \\ \frac{24 + 2 + 3 + 42 - 6}{6} = \frac{65}{6}$

Resposta final: 65/6