Question

$log \frac{1}{3} 81 = a \: \: \: calcule \: log_{16} {a}^{2}$


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Answer 1

Resposta:

$\log{1\over3}81=a\\ \\ ({1\over3}) ^{a}=81\\ \\ 3^{-a}=3^4\\ \\ -a=4\\ \\ a=-4\\ \\ --------------\\ \log_{16}a^2=\log_{16}(-4)^2=\log_{16}16=1$