Question

$log_{7} \binom{1}{49}$
​

Answer 1

Resposta:

-2

Explicação passo-a-passo:

1/49 = 1/7² = 7^-2

7^x = 7^-2

x = -2

Answer 2

Oie, Td Bom?!

$log_{7}( \frac{1}{49} )$

$log_{7}( \frac{1}{7 {}^{2} } )$

$log_{7}(7 {}^{ - 2} )$

➣$log_{a}(a {}^{x} ) = x \: . \: log_{a}(a)$

$- 2log_{7}(7)$

$- 2 \: . \: 1$

$- 2$

Att. Makaveli1996