Question

$log_{2}\sqrt[8]{64}$

Answer 1

Explicação passo-a-passo:

$\sf log_{2}~\sqrt[8]{64}=x$

$\sf 2^x=\sqrt[8]{64}$

$\sf 2^x=\sqrt[8]{2^6}$

$\sf 2^x=2^{\frac{6}{8}}$

Igualando os expoentes:

$\sf x=\dfrac{6}{8}$

$\sf x=\dfrac{3}{4}$