Question

$\lim_{x \to \o} \frac{e^{ax}-e^{bx}}{senax-senbx}$

Answer 1

$\underset{x\to0}\lim\ \dfrac{e^{ax}-e^{bx}}{\sin{ax}-\sin{bx}}=\underset{x\to0}\lim\ \dfrac{ae^{ax}-be^{bx}}{a\cos{ax}-b\cos{bx}}=\dfrac{a-b}{a-b}=1$