Question

$\lim_{x \to 1} \frac{ \sqrt[3]{x+2-1} }{x+1}$


Me ajudem a resolver essa conta por favor.

Answer 1

$\lim_{x \to 1} \frac{\sqrt[3]{x+2-1}}{x+1}=\frac{\sqrt[3]{1+2-1}}{1+1}=\frac{\sqrt[3]{2}}{2}=\frac{2^\frac{1}{3}}{2^1}=2^{-\frac{2}{3}$