Question

$\frac{x}{4} - (\frac{x + 1}{2} ) \leq ( \frac{1-x}{3} )$

Answer 1

$\frac{x}{4} -( \frac{x+1}{2} ) \leq ( \frac{1-x}{3}$

mmc(2,3,4) = 12

$3x -6(x+1) \leq 4(1-x)$

$3x -6x-6 \leq 4-4x$

$-3x+4x \leq 4+6$

$x \leq 10$