Question

$\frac{x-3}{2} +\frac{1}{x} = -3$

AJUDA AI PLELELELELESSS

Answer 1

Resposta:

• S = { -1, -2}

Vamos lá.

Explicação passo-a-passo:

1°) Faça o MMC:

MMC = 2x

2°) Utilize o MMC:

$\frac{(x-3).x}{2x} + \frac{1.2}{2x} = \frac{-3.2x}{2x}$

3°) Simplifique:

${(x-3).x} + {1.2} = {-3.2x}$

$x^{2}- 3x + 2= - 6x$

$x^{2}- 3x +6x+ 2= 0$

$x^{2} +3x+ 2= 0$

4°) Resolva:

$x^{2} +3x+ 2= 0$

a = 1

b = 3

c = 2

• Δ = b² -4.a.c

Δ = 3² - 4.1.2

Δ = 9 - 8

Δ = 1

• x = (-b) ± √Δ ÷ 2a

x = -3 ± 1 ÷ 2.a

$x' = \frac{ -3 + 1 }{2} = \frac{-2}{2} = -1$

$x'' = \frac{ -3 - 1 }{2} = \frac{-4}{2} = -2$

• Portanto, a solução : S = { -1, -2}

Answer 2

Oie, Td Bom?!

x-3/2 + 1/x = - 3

x-3/2 + 1/x + 3 = 0

x•(x - 3)/x•2 + 2•1/2x + 3/1 = 0

x•(x - 3)/2x + 2/2x + 2x•3/2x•1 = 0

x•(x - 3)/2x + 2/2x + 6x/2x = 0

x•(x - 3)+2+6x/2x = 0

x²-3x+2+6x/2x = 0

x²+3x+2/2x = 0

x² + 3x + 2 = 0

x² + 2x + x + 2 = 0

x • (x + 2) + x + 2 = 0

(x + 2) • (x + 1) = 0

x + 2 = 0

x + 1 = 0

x = - 2

x = - 1

S {x₁ = - 2 , x₂ = - 1}

Att. Makaveli1996