Question

$\frac{x - 1}{2} + \frac{x - 2}{3} = \frac{x - 3}{4}$
me ajudem a fazer a resolução​

Answer 1

$\frac{x - 1}{2} + \frac{x - 2}{3} = \frac{x - 3}{4} \\\\\mathsf{MMC = 12} \\\\\frac{6.(x - 1)}{12}+\frac{4.(x - 2)}{12} = \frac{3.(x - 3)}{12}\\\\ \frac{6x - 6+4x-8}{12} = \frac{3x-9}{12}\\\\\ \frac{10x-14}{12} = \frac{3x-9}{12}\\\\10x-14 = 3x-9\\\\7x = 14-9 \\\\ 7x = 5 \\\\\textsf{O valor de x:  } \boxed{x = \frac{5}{7}}$

Answer 2

Resposta:

x=5/7

Explicação passo-a-passo:

$\frac{x - 1}{2} + \frac{x - 2}{3} = \frac{x - 3}{4}$

(x-1)/2+(x-2)/3=(x-3)/4

mmc:

2,3,4/2

1,3,2/2

1,3,1/3

1,1,1/___

mmc(2,3,4)=2.2.4= 12

(x-1)/2+(x-2)/3=(x-3)/4

6.(x-1)+4.(x-2)=3.(x-3)

6x-6+4x-8=3x-9

6x+4x-6-8=3x-9

10x-14=3x-9

10x-3x=-9+14

7x= 5

x=5/7

Espero ter ajudado!