Question

$<var>\frac{x-1}{2} - \frac{(3x-x^2)}{3}=x+\frac{1}{3}</var>$

Answer 1

$\frac{x-1}{2} - \frac{(3x-x^2)}{3}=x+\frac{1}{3}$


$3(x-1)-2(3x-x^2)=6x+2$


$3x-3-6x+2x^2=6x+2$


$-3x-3+2x^2=6x+2$


$2x^2-9x-5=0$


$\delta=81+40$


$\delta=121$


$x=\frac{9+-11}{4}$


$x'=5$



$x"=\frac{1}{2}$