Question

$\frac{ \times {}^{2} }{5} \frac{ + 4}{ 5} = 2 - \times$
alguém ajuda, preciso em formula de Bhaskara!!! ​

Answer 1

Resposta:

S{-6,1}

Explicação passo-a-passo:

$\frac{ x^{2} }{5}+\frac{ 4}{ 5}=2-x\\\frac{ x^{2} +4}{5}=(2-x)\\x^2+4=5*(2-x)\\x^2+4=10-5x\\x^2+5x+4-10\\x^2+5x-6=0\\a=1\\b=5\\c=-6\\assim:\\\Delta=b^2-4*a*c\\\Delta=5^2-4*1*(-6)\\\Delta=25+24\\\Delta=49\\\sqrt{\Delta}=7\\Baskara:\\x=-\frac{b\pm\sqrt{\Delta}}{2*a}\\x=-\frac{5\pm7}{2*1}\\x=-\frac{5\pm7}{2}\\x'=\frac{-5+7}{2}=\frac{2}{2}=1\\x''=\frac{-5-7}{2}=\frac{-12}{2}=-6\\S{(-6,1)}$