Question

$\frac{6}{2+x} + \frac{2+x}{2-x} = \frac{x^2}{4-x^2}$

Answer 1

MMC: (4-x²)
Logo:
$\frac{6}{2+x}+ \frac{2+x}{2-x} = \frac{ x^{2}}{4- x^{2} }$ ⇒$\frac{6(2-x)+(2+x)(2+x)}{4- x^{2} } = \frac{ x^{2}}{4- x^{2}}$

6(2-x) + (2+x)(2-x) = x²
12-6x+4+2x+2x+x² = x²
16-2x+x²-x²*0
16-2x=0
-2x=-16 (-1)
2x=16
x= $\frac{16}{2}$
x=8