Question

${( - \frac{4}{ {x}^{2} }) }^{2}$
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Answer 1

$\left(-\frac{4}{x^2}\right)^2\\\\\left(-\frac{4}{x^2}\right)^2=\left(\frac{4}{x^2}\right)^2\\\\=\left(\frac{4}{x^2}\right)^2\\\\\left(\frac{4}{x^2}\right)^2=\frac{4^2}{\left(x^2\right)^2}\\\\4^2=16\\\\=\frac{16}{\left(x^2\right)^2}\\\\=\frac{16}{x^4}$