Question

$((( \frac{4 \frac{1}{2} + 2 \times \sqrt[5]{32} }{3}) \times {2}^{5} ) \times \sqrt[6]{64} ) \div {2}^{3} )$
​

Answer 1

Resposta:

$((( \frac{4 \frac{1}{2} + 2 \times \sqrt[5]{32} }{3}) \times {2}^{5} ) \times \sqrt[6]{64} ) \div {2}^{3} \\ ((( \frac{2 + 2 + 2}{3} ) \times 32 )\times 2) \div 8 \\ ((( \frac{6}{3} ) \times 32) \times 2) \div 8 \\ ((2 \times 32) \times 2) \div 8 \\ (64 \times 2) \div 8 \\ 128 \div 8 = 16</p><p>$

Espero ter ajudado

Answer 2

Resposta:

Letra E

Explicação passo-a-passo:

$((( \frac{4 \frac{1}{2} + 2 \times \sqrt[5]{32} }{3}) \times {2}^{5} ) \times \sqrt[6]{64} ) \div {2}^{3} ) = \\ ((( \frac{ \sqrt{4 } + 2 \times 2}{3} ) \times {2}^{5} ) \times 2) \div {2}^{3} = \\ ((( \frac{2 + 4}{3} ) \times {2}^{5} ) \times 2) \div {2}^{3} = \\ ((2 \times {2}^{5} ) \times 2) \div {2}^{3} = \\ ({2}^{6} \times 2) \div {2}^{3} = \\ {2}^{7} \div {2}^{3} \\ {2}^{4} = 16$

Espero ter ajudado!