Question

$\frac{3x + 1}{4} - 1 < \frac{1}{2} - 2x$
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Answer 1

Resposta:

$\frac{3x + 1}{4} - 1 < \frac{1}{2} - 2x \\ \frac{3x + 1}{4} + 2x < \frac{1}{2} + 1 \\ \frac{3x + 1}{4} + \frac{2x}{1} < \frac{1}{2} + \frac{1}{1} \\ \frac{3x + 1}{4} + \frac{8x}{4} < \frac{1}{2} + \frac{2}{2} \\ \frac{11x + 1}{4} < \frac{3}{2} \\ 4 \times \frac{11x + 1}{4} < 4 \times \frac{3}{2} \\ 11x + 1 < 4 \times \frac{3}{2} \\ 11x + 1 < 2 \times 3 \\ 11x < 6 - 1 \\ 11x < 5 \\ x < \frac{5}{11}$