Question

$\frac{2^{x+3} + 2^{x+2}- 2^{x-1}}{2^{x-2}+2^{x}}$

Answer 1

Resposta:

Desmembrando

${2^x.2^3+2^x.2^2-2^x.2~{-1}\over2^x.2^{-2}+2^x}=\\ \\ 2^x~~como~~fator~~comum\\ \\ {2^x(2^3+2^2-2^{-1})\over2^x(2^{-2}+1)}=\\ \\ cancela~~2^x\\ \\ (8+4-{1\over2})\div({1\over4}+1)=\\ \\ ({16+8-1\over2})\div({1+4\over4})=\\ \\ {23\over2}\div{5\over4}=\\ \\ {23\over\not2}\times{\not4^2\over5}=\fbox{ {46\over5} }$