Question

$\frac{2}{ x^{2} - 1} + \frac{1}{x+1} + 1= 0$

Answer 1

$\frac{2}{x^2-1}+\frac{1}{x+1}+1=0\\ \\ \boxed{mmc=x^2-1}\\ \\ 2+x-1+x^2-1=0\\ \\ x^2+x=0\\ \\ x(x+1)=0\\ \\ x=0 \ \ \ ou \ \ \ \ x=-1$