Question

$( \frac{1}{4} \div \frac{9}{32} - \frac{10}{9} \times \frac{2}{5}) {}^{3} \times \sqrt{ \frac{81}{256} }$
como eu posso resolver essa conta??

Answer 1

boa tarde princesa !!!!

$( \frac{1}{4} \div \frac{9}{32} - \frac{10}{9} \times \frac{2}{5} ) {}^{3} \times \sqrt{ \frac{81}{256} } \\ \\ ( \frac{1}{4} \times \frac{32}{9} - \frac{2}{9} \times 2) {}^{3} \times \frac{9}{16} \\ \\ ( \frac{8}{9} - \frac{4}{9} ) {}^{3} \times \frac{9}{2 {}^{4} } \\ \\ ( \frac{4}{9} ) {}^{3} \times \frac{9}{2 {}^{4} } \\ \\ \frac{4 {}^{3} }{9 {}^{3} } \times \frac{9}{2 {}^{4} } \\ \\ \frac{(2 {}^{2}) }{9 {}^{2} } \times \frac{1}{2 {}^{4} } \\ \\ \frac{2 {}^{6} }{9 {}^{2} } \times \frac{1}{2 {}^{4} } \\ \\ \frac{2 {}^{2} }{9 {}^{2} } \\ \\ = \frac{4}{81}$

espero que eu tenha conseguido te ajudar....

Answer 2

$( \frac{1}{4} : \frac{9}{32} - \frac{10}{9}. \frac{2}{5})^{3}. \sqrt{ \frac{81}{256} } = ( \frac{8}{9} - \frac{4}{9})^{3}.\frac{9}{16} = (\frac{4}{9})^{3}.\frac{9}{16} = \frac{64}{729}.\frac{9}{16} = \frac{549^{:9} }{11664^{:9}} = \frac{4}{81}$

Espero ter ajudado!